Answer
(a) $5^{-3}=\dfrac{1}{125}$
(b) $8^{\frac{2}{3}}=4$
Work Step by Step
RECALL:
$\log_b{x}=y \longrightarrow b^y=x$
Use the rule above to obtain:
(a) $5^{-3}=\dfrac{1}{125}$
(b) $8^{\frac{2}{3}}=4$
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