## College Algebra 7th Edition

$a.\quad x-a$ $b.\quad(x-a)^{m}$
$a$ is a zero of $P$ if and only if $x-a$ is a factor of $P(x)$ . (Factor theorem) If the zero $a$ has multiplicity $m$, then $(x-a)^{m}$ is a factor of P. $a.\quad x-a$ $b.\quad(x-a)^{m}$