## College Algebra 7th Edition

a) The zeros of the function are: $\{2,-1+\sqrt 3i, -1-\sqrt 3i\}$ b) $P(x)=(x-2)(x^{2}+2x+4)$
(a) Zeros Factor the polynomial completely to obtain: $P(x)=x^{3}-8=(x-2)(x^{2}+2x+4)$ $x-2=0 \rightarrow x=2$ $x^{2}+2x+4=0 \rightarrow x=-1\pm\sqrt 3i$ Thus, the zeros of the function are: $\{2,-1+\sqrt 3i, -1-\sqrt 3i\}$ (b) Completely Factored Form From part (a) above, the completely factored form of P(x) is: $P(x)=(x-2)(x^{2}+2x+4)$