## College Algebra 7th Edition

g(f(x)) = g($\frac{1}{x}$) = $\frac{1}{\frac{1}{x}}$ =x f(g(x)) = f($\frac{1}{x}$) = $\frac{1}{\frac{1}{x}}$ =x Since g(f(x)) = f(g(x)), f and g are inverses of each other