## College Algebra 7th Edition

$f^{-1}(3)$ = 1
f(x) = 5 - 2x is one to one Now find the inverse of f(x) y = 5 - 2x y - 5 = -2x $\frac{y - 5}{-2}$ = x $f^{-1}(x)$ = $\frac{x - 5}{-2}$ $f^{-1}(3)$ = $\frac{3 - 5}{-2}$ $f^{-1}(3)$ = 1