## College Algebra 7th Edition

$[0, 3 ]$
We are given: $f(x)=\sqrt{x}+\sqrt{3-x}$ The domain of $\sqrt{x}$ is $[0,\ \infty)$. The domain of $\sqrt{3-x}$ is $(-\infty, 3]$. Therefore, the domain of $f(x)$ is the intersection of the two domains: $(-\infty,\ 3]\cap [0,\ \infty)=[0, 3 ]$