College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.7 - Combining Functions - 2.7 Exercises: 1

Answer

(f + g)(2) = 8 (f - g)(2) = -2 (fg)(2) = 15 $(\frac{f}{g})$(2) = $\frac{3}{5}$

Work Step by Step

f(2) = 3 and g(2) = 5 (f + g)(2) = f(2) + g(2) = 3 + 5 = 8 (f - g)(2) = f(2) - g(2) = 3 - 5 = -2 (fg)(2) = f(2) $\times$ g(2) = 3 $\times$ 5 = 15 $(\frac{f}{g})$(2) = $\frac{f(2)}{g(2)}$ = $\frac{3}{5}$
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