College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.4 - Average Rate of Change of a Function - 2.4 Exercises: 29

Answer

$-\frac{1}{4}$ ft/day

Work Step by Step

We see from the graph that $W(200)=50$ and $W(100)=75$. We use this information to find the average rate of change for this interval: $\displaystyle \frac{W(200)-W(100)}{200-100}=\frac{50-75}{200-100}=\frac{-25}{100}=-\frac{1}{4}$ ft/day
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