College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.4 - Average Rate of Change of a Function - 2.4 Exercises: 18

Answer

(a) -16 (b) -4

Work Step by Step

We are given: $g(t)=t^4-t^3+t^2$; $t=-2$, $t=2$ (a) We calculate the net change: $g(2)-g(-2)=[2^{4}-2^{3}+2^{2}]-[(-2)^{4}-(-2)^{3}+(-2)^{2}]=12-28=(16-8+4)-(16--8+4)=-16$ (b) We calculate the average rate of change: $\displaystyle \frac{g(2)-g(-2)}{2--2}=\frac{-16}{4}=-4$
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