Answer
$k(0)=0$
$k(3)=27$
$k(-3)=-81$
$k(\frac{1}{2})=\frac{-1}{2}$
$k(\frac{a}{2})=\frac{a^{3}}{4}-\frac{3a^{2}}{4}$
$k(-x)=-2x^{3}-3x^{2}$
$k(x^{3})=2x^{9}-3x^{2}$
Work Step by Step
We are given $2x^{3}-3x^{2}$
We evaluate:
$k(0)=2(0)^{3}-3(0)^{2}=0$
$k(3)=2(3)^{3}-3(3)^{2}=27$
$k(-3)=2(-3)^{3}-3(-3)^{2}=-81$
$k(\frac{1}{2})=2(\frac{1}{2})^{3}-3(\frac{1}{2})^{2}=\frac{-1}{2}$
$k(\frac{a}{2})=2(\frac{a}{2})^{3}-3(\frac{a}{2})^{2}=\frac{a^{3}}{4}-\frac{3a^{2}}{4}$
$k(-x)=2(-x)^{3}-3(-x)^{2}=-2x^{3}-3x^{2}$
$k(x^{3})=2(x^{3})^{3}-3(x^{3})^{2}=2x^{9}-3x^{2}$
