College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.1 - Functions - 2.1 Exercises: 26

Answer

$g(-2)=0$ $g(2)=$ undefined $g(0)=-1$ $g(a)=\frac{a+2}{a-2}$ $g(a^{2}-2)=\frac{a^{2}}{a^{2}-4}$ $g(a+1)=\frac{a+3}{a-1}$

Work Step by Step

We are given: $g(t)= \frac{t+2}{t-2}$ We evaluate: $g(-2)=\frac{-2+2}{-2-2}=0$ $g(2)=\frac{2+2}{2-2}=\frac{4}{0}$= undefined $g(0)= \frac{0+2}{0-2}=\frac{2}{-2}=-1$ $g(a)=\frac{a+2}{a-2}$ $g(a^{2}-2)= \frac{a^{2}-2+2}{a^{2}-2-2}=\frac{a^{2}}{a^{2}-4}$ $g(a+1)=\frac{a+1+2}{a+1-2}=\frac{a+3}{a-1}$
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