College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.1 - Functions - 2.1 Exercises - Page 191: 4

Answer

a) Subtract 4, then square and add 3. b) $f(2)=7$ $f(4)=3$ $f(6)=7$

Work Step by Step

a) Since the function is $f(x)=(x-4)^2+3$, in order to solve for a value, you must subtract 4 from it first, square it and then add three. b) $f(2)=(2-4)^2+3=7$ $f(4)=(4-4)^2+3=3$ $f(6)=(6-4)^2+3=7$
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