## College Algebra 7th Edition

(a) 5 is not in the domain of $h$, but is in the domain of $f$ and $g$. (b) $f(5)=10$, $g(5)=0$
We test if $5$ is in the domain of the functions by plugging it in: $f(x)=x^2-3x$ $f(5)=5^{2}-3(5)=25-15=10$ $g(x)=\frac{x-5}{x}$ $g(5)=\frac{5-5}{5}=\frac{0}{5}=0$ $h(x)=\sqrt{x-10}$ $h(5)=\sqrt{5-10}=\sqrt{-5}$ Since we don't get a real number for $h$, 5 is not in the domain of $h$ (but is in the domain of $f$ and $g$). (b) We found the values in (a).