## College Algebra 7th Edition

$f^{-1}(x)= \frac{1}{3}(x+2)$
We are given: $f(x)=3x-2$ To find the inverse function, we switch $x$ and $y$ and solve for $y$: $y=3x-2$ $x=3y-2$ $x+2=3y$ $y=\frac{x+2}{3}=\frac{1}{3}(x+2)$ Thus the inverse is: $f^{-1}(x)= \frac{1}{3}(x+2)$