## College Algebra 7th Edition

$f^{-1}(0)=1$ $f^{-1}(4)=3$
We know that $f$ does have an inverse because it passes the horizontal line test (is one-to-one). We know that $f(1)=0$. Therefore, $f^{-1}(0)=1$. Similarly, we know that $f(3)=4$. Therefore, $f^{-1}(4)=3$.