## College Algebra 7th Edition

minimum: $(-1,-7)$
We are given: $g(x)=2x^{2}+4x-5$ We factor by completing the square: $2(x^{2}+2x)-5$ $2(x^{2}+2x+1)-5-2$ $2(x+1)^{2}-7$ We see that this is a transformed parabola: $x^2$ moved left 1 unit and down 7 units. Thus the minimum would occur at $(-1,-7)$.