College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Chapter 2 Review - Exercises - Page 269: 67

Answer

a) $P(10)=5010$ $P(20)=7040$ b) $203~people/year$

Work Step by Step

a) Plugging in $t=10,20$ into the population formula, we get: $P(10)=3000+200(10)+0.1(10)^2=5010$ $P(20)=3000+200(20)+0.1(20)^2=7040$ These values represent the population in 1995 and 2005, respectively. b) The rate of change is: $\frac{f(y)-f(x)}{y-x}=\frac{7040-5010}{20-10}=203~people/year$ This value represents the average annual increase (people per year).
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