College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.9 - Solving Equations and Inequalities Graphically - 1.9 Exercises - Page 159: 36


$(-1, -0.25) \cup(-0.25, +\infty)$

Work Step by Step

Add $9x+1$ to both sides of the inequality to obtain: $16x^3+24x^2+9x+1\gt -9x-1+9x+1 \\16x^3+24x^2+9x+1\gt 0 $ Graph the function $y=16x^3+24x^2+9x+1$ (refer to the attached image below for the graph) The solution to the given inequality is the set of x-values for which $y\gt 0$. Notice that the graph shows $y \gt 0$ in the following intervals: $(-1, -0.25)$ and $(-0.25, +\infty)$
Small 1511843602
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.