## College Algebra 7th Edition

$(-\infty, 1] \cup [2, 3]$
Subtract $6x^2+6$ to both sides of the inequality to obtain: $x^3+11x-6x^2-6\le 0 \\x^3-6x^2+11x-6\le0$ Graph the function $y=x^3-6x^2+11x-6$ (refer to the attached image below for the graph) The solution to the given inequality is the set of x-values for which $y\le0$. Notice that $y \le 0$ in the following intervals: $(-\infty, 1]$ and $[2, 3]$