## College Algebra 7th Edition

$\frac{a-c}{b}\leq x\lt \frac{2a-c}{b}$
$a\leq bx+c<2a$ We subtract $c$ from all sides: $\displaystyle a-c\leq bx\lt 2a-c$ And divide by $b$: $\frac{a-c}{b}\leq x\lt \frac{2a-c}{b}$