#### Answer

$x\geq\frac{c}{a}+\frac{c}{b}$

#### Work Step by Step

$a(bx-c)\geq bc$
We divide by $a$:
$bx-c\geq\frac{bc}{a}$
Next we add $c$:
$bx\geq\frac{bc}{a}+c$
And divide by $b$:
$x\geq\frac{1}{b}(\frac{bc}{a}+c)$
$x\geq\frac{c}{a}+\frac{c}{b}$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$x\geq\frac{c}{a}+\frac{c}{b}$

You can help us out by revising, improving and updating this answer.

Update this answerAfter you claim an answer you’ll have **24 hours** to send in a draft. An editor
will review the submission and either publish your submission or provide feedback.