Answer
$x\geq\frac{c}{a}+\frac{c}{b}$
Work Step by Step
$a(bx-c)\geq bc$
We divide by $a$:
$bx-c\geq\frac{bc}{a}$
Next we add $c$:
$bx\geq\frac{bc}{a}+c$
And divide by $b$:
$x\geq\frac{1}{b}(\frac{bc}{a}+c)$
$x\geq\frac{c}{a}+\frac{c}{b}$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 1, Equations and Graphs - Section 1.7 - Solving Inequalities - 1.7 Exercises - Page 149: 77
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