## College Algebra 7th Edition

$x\geq\frac{c}{a}+\frac{c}{b}$
$a(bx-c)\geq bc$ We divide by $a$: $bx-c\geq\frac{bc}{a}$ Next we add $c$: $bx\geq\frac{bc}{a}+c$ And divide by $b$: $x\geq\frac{1}{b}(\frac{bc}{a}+c)$ $x\geq\frac{c}{a}+\frac{c}{b}$