College Algebra 7th Edition

a) We must add $3$ to the x- and $2$ to the y-coordinate. Thus it will become $(5+3,3+2)=(8,5)$ b) We must add $3$ to the x- and $2$ to the y-coordinate. Thus it will become $(a+3,b+2)$ c) We must add $3$ to the x- and $2$ to the y-coordinate. Thus it will become $(-3+3,0+2)=(0,2)$ d) We must add $3$ to the x- and $2$ to the y-coordinate. Thus they will become $A(-2,1),B(0,4),C(5,3)$