College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.1 - The Coordinate Plane - 1.1 Exercises - Page 93: 48

Answer

$B=(10,13)$.

Work Step by Step

Let $B=(x,y)$. Since (6,8) is the midpoint of AB, $(6,8)=(\displaystyle \frac{2+x}{2}, \frac{3+y}{2})$ Equating the x-coordinates, $6=\displaystyle \frac{2+x}{2}$ $12=2+x$ $x=10$. Equating the y-coordinates, $8=\displaystyle \frac{3+y}{2}$ $16=3+y$ $y=13$. So, $B=(10,13)$.
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