## College Algebra (6th Edition)

Published by Pearson

# Chapter P - Summary, Review, and Test - Test - Page 91: 9

#### Answer

$\frac{15-3\sqrt 2}{23}$

#### Work Step by Step

Multiply the top and bottom by the conjugate of the denominator to simplify. $\frac{3}{5+\sqrt 2}$ $\frac{3}{5+\sqrt 2}\times\frac{5-\sqrt 2}{5-\sqrt 2}$ $\frac{15-3\sqrt 2}{25-2}$ $\frac{15-3\sqrt 2}{23}$

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