College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Test: 9

Answer

$\frac{15-3\sqrt 2}{23}$

Work Step by Step

Multiply the top and bottom by the conjugate of the denominator to simplify. $\frac{3}{5+\sqrt 2}$ $\frac{3}{5+\sqrt 2}\times\frac{5-\sqrt 2}{5-\sqrt 2}$ $\frac{15-3\sqrt 2}{25-2}$ $\frac{15-3\sqrt 2}{23}$
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