College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Test - Page 91: 24



Work Step by Step

Separate the terms into two groups. Factor the first group by trial and error. Then use the formula $a^2-b^2=(a+b)(a-b)$ to factor further. $x^2+10x+25-9y^2$ $(x^2+10x+25)-9y^2$ $(x+5)(x+5)-9y^2$ $(x+5)^2-9y^2$ $(x+5+3y)(x+5-3y)$
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