College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Test - Page 91: 15

Answer

$\frac{2x+6}{x+1}$

Work Step by Step

To multiply, change the second term to its reciprocal. Then factor all parts of each term, and then multiply and divide out common values. To finish, recombine the numerator. $\frac{2x+8}{x-3}\div\frac{x^2+5x+4}{x^2-9}$ $\frac{2x+8}{x-3}\times\frac{x^2-9}{x^2+5x+4}$ $\frac{2(x+4)}{x-3}\times\frac{(x+3)(x-3)}{(x+4)(x+1)}$ $\frac{2(x+4)(x+3)(x-3)}{(x-3)(x+4)(x+1)}$ $\frac{2(x+3)}{x+1}$ $\frac{2x+6}{x+1}$
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