College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.5 - Page 74: 87


(9$b^{2}$$x$ + 9$b^{2}$$y$) - (16$y$ + 16$x$) = 9$b^{2}$($x$ + $y$) - 16($x$ + $y$) = (9$b^{2}$ - 16)($x$ + $y$) = (3$b$ + 4)(3$b$ - 4)($x$ + $y$)

Work Step by Step

To factor this polynomial, start by grouping like terms. In this case, we will factor our the greatest common factor of each group. Now we will have two polynomial pairs factored, but the first of the pairs can still be simplified. Use the formula A^2 - B^2 = (A + B)(A - B) to factor out that pair, and then you will have your answer.
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