## College Algebra (6th Edition)

$(4x+3)(16x^{2}-12x+9)$
If $a$ and $b$ are real numbers, we know that $a^{3}+b^{3}=(a+b)(a^{2}-ab+b^{2})$. Therefore, we know that $64x^{3}+27=(4x+3)((4x)^{2}-4x\times3+(3)^{2})=(4x+3)(16x^{2}-12x+9)$. In this case, $a=4x$ and $b=3$.