College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.4 - Page 61: 88



Work Step by Step

$$(3x+4)(3x-4)(9x^2+16)$$ To multiply the sum of two terms by the difference of two terms, use the formula: $(a+b)(a-b)=a^2-b^2$: $$=[(3x)^2-(4)^2](9x^2+16)$$ $$=(9x^2-16)(9x^2+16)$$ Another product of the sum and difference of two terms! $$=(9x^2)^2-(16)^2$$ $$=81x^4-256$$
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