College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.4: 38



Work Step by Step

$$(3x^2+4x)(3x^2-4x)$$ $$=(3x^2\times 3x^2)+(3x^2\times (-4x))+(4x\times 3x^2)+(4x\times (-4x))$$ $$=9x^4-12x^3+12x^3-16x^2$$ $$=9x^4-16x^2$$
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