College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.4 - Page 61: 13


$6x^2-6x+2$; Degree 2

Work Step by Step

$$(5x^2-7x-8)+(2x^2-3x+7)-(x^2-4x-3)$$ $$=(5x^2+2x^2-x^2)+(-7x-3x-(-4x))+(-8+7-(-3))$$ $$=6x^2+(-10x+4x)+(-1+3)$$ $$=6x^2-6x+2$$
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