College Algebra (6th Edition)

Probability of getting two numbers whose sum is 4 = $\frac{5}{36}$
Total number of outcomes = 36 Favorable outcomes if sum of two numbers is 6 = (1, 5), (2, 4), (3, 3), (4, 2), (5, 1) = 5 Probability = $\frac{Number of favorable outcomes}{total number of outcomes}$ Probability of getting two numbers whose sum is 4 = $\frac{5}{36}$