Answer
Probability of getting two numbers whose sum is 4 = $\frac{1}{12}$
Work Step by Step
Total number of outcomes = 36
Favorable outcomes if sum of two numbers is 4 = (1, 3), (2, 2), (3, 1) = 3
Probability = $\frac{Number of favorable outcomes}{total number of outcomes}$
Probability of getting two numbers whose sum is 4 = $\frac{3}{36}$
= $\frac{1}{12}$
