Answer
Probability of selecting a family with at least two female children = $\frac{1}{2}$
Work Step by Step
Total outcomes = (MMM, MMF, MFM, FMM, MFF, FMF, FFM, FFF) = 8
For selecting a family with at least two female children, the favorable outcomes = (FFF, MFF, FMF, FFM, ) = 4
Probability = $\frac{Favorable outcomes}{total outcomes}$
Probability of selecting a family with at least two female children
= $\frac{4}{8}$
= $\frac{1}{2}$
