College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.6 - Page 769: 56

Answer

The number of different possible selections (6 out of 59) = $59_{{C}{_{6}}}$ = 45,057,474

Work Step by Step

Total number of collection = 59 Numbers have to select = 6 The number of different possible selections (6 out of 59) = $59_{{C}{_{6}}}$ = $\frac{59!}{(59 - 6)! 6!}$ = $\frac{59!}{53!. 6!}$ = $\frac{59\times58\times57\times56\times55\times54\times53!}{ 53!.(6\times5\times4\times3\times2\times1)}$ = $\frac{59\times58\times57\times56\times55\times54}{ 6\times5\times4\times3\times2\times1}$ = 45057474
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