College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.6 - Page 769: 55

Answer

The number of possible selections (6 out of 53) = $53_{{C}{_{6}}}$ = 22,957,480

Work Step by Step

Total number of collections = 53 Numbers have to select = 6 The number of possible selections (6 out of 53) = $53_{{C}{_{6}}}$ = $\frac{53!}{(53 - 6)! 6!}$ = $\frac{53!}{47!. 6!}$ = $\frac{53\times52\times51\times50\times49\times48\times47!}{ 47!.(6\times5\times4\times3\times2\times1)}$ = $\frac{53\times52\times51\times50\times49\times48}{ 6\times5\times4\times3\times2\times1}$ = 22957480
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