College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.6 - Page 769: 49

Answer

Number of ways to elect 3 out of six = $6_{{C}{_{3}}}$ = 20

Work Step by Step

Total number of candidates = 6 Number of candidates to be elected = 3 Number of ways to elect 3 out of six = $6_{{C}{_{3}}}$ = $\frac{6!}{(6 - 3)! .3!}$ = $\frac{6!}{3! .3!}$ = $\frac{6\times5\times4\times3!}{3! .3\times2\times1}$ = 20
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