Answer
$64a^6+192a^5b+240a^4b^2+160a^3b^3+60a^2b^4+12ab^5+b^6$
Work Step by Step
Use the binomial theorem formula (detailed on page 754) to solve the problem. Be careful in writing each term correctly.
$(2a+b)^6$
$1*(2a)^6+6*(2a)^5*(b)+15*(2a)^4*(b)^2+20*(2a)^3*(b)^3+15*(2a)^2*(b)^4+6*(2a)*(b)^5+1(b)^6$
$64a^6+192a^5b+240a^4b^2+160a^3b^3+60a^2b^4+12ab^5+b^6$
