Answer
$x^5-10x^4+40x^3-80x^2+80x-32$
Work Step by Step
Use the binomial theorem formula (detailed on page 754) to solve the problem. Be careful in writing each term correctly.
$(x-2)^5$
$1*(x)^5+5*(x)^4*(-2)+10*(x)^3*(-2)^2+10*(x)^2*(-2)^3+5*(x)*(-2)^4+1*(-2)^5$
$x^5-10x^4+40x^3-80x^2+80x-32$