Answer
$c^5+15c^4+90c^3+270c^2+405c+243$
Work Step by Step
Use the binomial theorem formula (detailed on page 754) to solve the problem. Be careful in writing each term correctly.
$(c+3)^5$
$1*(c)^5+5*(c)^4*(3)+10*(c)^3*(3)^2+10*(c)^2*(3)^3+5*(c)*(3)^4+1*(3)^5$
$c^5+15c^4+90c^3+270c^2+405c+243$
