College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.4 - Page 751: 7

Answer

See below.

Work Step by Step

$S_k:3+7+11+...+(4k-1)=k(2k+1)$ $S_{k+1}:3+7+11+...+(4(k+1)-1)=(k+1)(2(k+1)+1)\\S_{k+1}:3+7+11+...+(4k+3)=(k+1)(2k+3)$
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