College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.4 - Page 751: 2


See below.

Work Step by Step

$S_1:3=\frac{1(1+5)}{2}=\frac{6}{2}$, thus this is true $S_2:3+4=7=\frac{2(2+5)}{2}=\frac{14}{2}$, thus this is true $S_3:3+4+5=12=\frac{3(3+5)}{2}=\frac{24}{2}$, thus this is true
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