Answer
See below.
Work Step by Step
$S_k:4+8+12+...+4k=2k(k+1)$
$S_{k+1}:4+8+12+...+4(k+1)=2(k+1)((k+1)+1)\\S_{k+1}:4+8+12+...+(4k+4)=2(k+1)(k+2)$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.4 - Page 751: 5
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