College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.3 - Page 739: 26



Work Step by Step

First, we must determine the common ratio between the terms: $r=\frac{6}{3}=\frac{12}{6}=\frac{24}{12}=2$ For solving this, we will use the formula for the $nth$ term of the geometric series. $S_{n}=\frac{a_{1}\times (1-r^{n})}{1-r}$. Then put correct value for $7th$ term to solve. $S_{12}=\frac{2 \times (1-2^{12})}{1-2}=8190$
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