College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.3 - Page 739: 20



Work Step by Step

First, we must determine the common ratio between the terms: $r=\frac{6}{12}=\frac{3}{6}=\frac{(\frac{3}{2})}{3}=\frac{1}{2}$ For solving this, we will use the formula for the $nth$ term of the geometric series. $a_{n}=a_{1}\times r^{n-1}$. Then put correct value for $7th$ term to solve. $a_{7}=12 \times (\frac{1}{2})^{7-1}=0.1875$
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