College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.3 - Page 739: 19

Answer

$0.025$

Work Step by Step

First, we must determine the common ratio between the terms: $r=\frac{6}{18}=\frac{2}{6}=\frac{(\frac{2}{3})}{2}=\frac{1}{3}$ For solving this, we will use the formula for the $nth$ term of the geometric series. $a_{n}=a_{1}\times r^{n-1}$. Then put correct value for $7th$ term to solve. $a_{7}=18 \times (\frac{1}{3})^{7-1}=0.025$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.