College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.2: 49

Answer

$4,8,12,16,....400$ $S_{100}= 20200$

Work Step by Step

Sequence: $4,8,12,16, ... 400$ $S_{100} = 4+8+12+....+400$ Sum of $n$ terms, $S_{n}= \frac{n}{2}(a_{1}+a_{n})$ $S_{100}= \frac{100}{2}(4+400)$ $S_{100}= 50(404)$ $S_{100}= 20200$
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