Answer
$4,8,12,16,....400$
$S_{100}= 20200$
Work Step by Step
Sequence: $4,8,12,16, ... 400$
$S_{100} = 4+8+12+....+400$
Sum of $n$ terms,
$S_{n}= \frac{n}{2}(a_{1}+a_{n})$
$S_{100}= \frac{100}{2}(4+400)$
$S_{100}= 50(404)$
$S_{100}= 20200$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.2 - Page 725: 49
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