## College Algebra (6th Edition)

Given i = 1 to 5 for $\frac{(i + 2)!}{i!}$ The sum = $\frac{(1 + 2)!}{1!}$ + $\frac{(2 + 2)!}{2!}$ + $\frac{(3 + 2)!}{3!}$ + $\frac{(4 + 2)!}{4!}$ + $\frac{(5 + 2)!}{5!}$ = $\frac{3!}{1!}$ + $\frac{4!}{2!}$ + $\frac{5!}{3!}$ + $\frac{6!}{4!}$ + $\frac{7!}{5!}$ = $\frac{6}{1}$ + $\frac{24}{2}$ + $\frac{120}{6}$ + $\frac{720}{24}$ + $\frac{5040}{120}$ = 6 + 12 + 20 + 30 + 42 = 110