College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.1 - Page 714: 25

Answer

120

Work Step by Step

To solve the expression we will break down factorials and cancel same terms. $\frac{16\times15\times14!}{2!\times14!}$ =$\frac{16 \times15}{2\times1}$
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