College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Concept and Vocabulary Check - Page 750: 5

Answer

See below.

Work Step by Step

$k^2+3k+2=(k^2+k)+((k^2+3k+2)-(k^2+k)=(k^2+k)+(2k+2)=k^2+k+2(k+1)$
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